assembly - Store Strings in MIPS -

i short.

i making program in mips intake strings of 15 chars user. unable save string on stack. note using 2d matrix [20][15] 20 string , each string have 15 character.

please guide me. have been trying on past 10 hours.

loop: bgt $t2,20,xyz  li $v0,8        #take in input la $a0, buffer  #load byte space address li $a1, 15      # allot byte space string syscall  move $t3,$a0    #save string t0   #transfering data onto stack!  #num = $t2 #$base address of matrix = $t1 #colums of matrix = 15  mul $s0,$t2,15      #num * colums li $s1,4            #string have 4 bit! mul $s0,$s0,$s1  add $s0,$s0,$t1     #$t1 base address!  #storing data onto stack! sw $t3,0($s0)  add $t2,$t2,1 add $s0,$s0,-15  j loop 

you're storing address of string on stack, not string itself

t3 set by:

la $a0, buffer  #load byte space address move $t3,$a0    #save string t0 

storing instruction:

sw $t3,0($s0) 

this next instruction assumes 15 bytes written:

add $s0,$s0,-15  

you wrote 4 bytes sw $t2,0($s0). gets destroyed in next loop anyway recalculate , overwrite s0 based on t2. making add $s0,$s0,-15 redundant.

you need string copy routine like

#a0=dest, a1=source copy_string:    lbu v0,(a1)        addiu a1,a1,#1       sb v0,(a0)    addiu a0,a0,#1    bnez v0, copy_string