regex - Regular expression java to extract the balance from a string -

i have string contains " dear user bal= 1,234/ ".
want extract 1,234 string using regular expression. can 1,23, 1,2345, 5,213 or 500

final pattern p=pattern.compile("((bal)=*(\\s{1}\\w+))"); final matcherm m = p.matcher(text); if(m.find())     return m.group(3); else  return ""; 

this returns 3.
regular expression should make? new regular expressions.

you search in regex word characters \w+ should search digits \d+.

additionally there comma, need match well.

i'd use

/.bal=\s([\d,]+(?=/)./

as pattern , number in resulting group.

explanation: .* match before bal= match string "bal=" \s match whitespace ( start matching group [\d,]+ matches every digit or comma 1 ore more times (?=/) match former if followed slash ) end matching group .* matches thereaft

this untestet, should work this:

final pattern p=pattern.compile(".*bal=\\s([\\d,]+(?=/)).*"); final matcherm m = p.matcher(text); if(m.find())     return m.group(1); else  return ""; 

according online tester, pattern above matches text:

bal= 1,234/