python - how to dynamically generate a subclass in a function? -

i'm attempting write function creates new subclass named string gets passed argument. don't know tools best this, gave shot in code below , managed make subclass named "x", instead of "mysubclass" intended. how can write function correctly?

class mysuperclass:     def __init__(self,attribute1):         self.attribute1 = attribute1  def makenewclass(x):     class x(mysuperclass):         def __init__(self,attribute1,attribute2):             self.attribute2 = attribute2  x = "mysubclass" makenewclass(x) myinstance = mysubclass(1,2) 

the safest , easiest way use type builtin function. takes optional second argument (tuple of base classes), , third argument (dict of functions). recommendation following:

def makenewclass(x):     def init(self,attribute1,attribute2):         # make sure call base class constructor here          self.attribute2 = attribute2      # make new type , return     return type(x, (mysuperclass,), {'__init__': init})  x = "mysubclass" mysubclass = makenewclass(x) 

you need populate third argument's dict want new class have. it's generating classes , want push them list, names won't matter. don't know use case though.

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alternatively access globals , put new class instead. strangely dynamic way generate classes, best way can think of seem want.

def makenewclass(x):     def init(self,attribute1,attribute2):         # make sure call base class constructor here          self.attribute2 = attribute2      globals()[x] = type(x, (mysuperclass,), {'__init__': init})