scala - Returning the same value type, but with success/failure -

let's have method..

def foo(b: bar): try[bar] = ??? 

try placeholder here. foo bar, returns value indicate success/failure. want return original value success/failure indication, when have collection, can know which ones failed , succeeded, , them. try doesn't work me, because failure wraps exception (let's don't care reason why failed).

i maybe return either[bar, bar], seems redundant repeat type parameter.

are there better alternatives this?

either[bar, bar] , (boolean, bar) isomorphic , choice between them matter of taste.

i'd prefer either because nicer set of operations mapping on collection pattern matching, etc., merge extension method allows write results.map(_.merge) seq[bar] if in situation no longer need make distinction between successful , failed results. find this:

val result: either[bar, bar] = foo(input).tooption.toright(input) 

a little nicer than:

val result: (boolean, bar) =   foo(input).map((true, _)).getorelse((false, input)) 

or alternatives, mileage may vary.