need to explain bash grep regular expression grep -E '(^|[^0-9.])'2 *.c -

i'm confused grep command. explain me.

for each digit i, search (nondigit)i sequence in textd.sh)

grep -e '(^|[^0-9.])'i *.c  in 0 1 2 3 4 5 6 7 8 9;    grep -e '(^|[^0-9.])'$i *.c > lines_with_${i} done

this grep command:

grep -e '(^|[^0-9.])'$i *.c

is matching digits 0, 1, 2, 3,.... in loop.

while matching these digits makes sure digits either @ start (^) or else there non-digit non-dot character before these digits ([^0-9.]).

so example match:

abc 1 2 def5

and won't match:

abc.1

Unity